Which of the following is not expected to be | vedclass

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(D) The reaction is a solvolysis of $1$-iodo-$1$-methylcyclohexane in water. Step $1$: The leaving group $I^-$ departs to form a secondary carbocation

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(D) The reaction is a solvolysis of $1$-iodo-$1$-methylcyclohexane in water. Step $1$: The leaving group $I^-$ departs to form a secondary carbocation at the $C_2$ position. Step $2$: $A$ $1,2$-hydride shift occurs to transform the secondary carbocation into a more stable tertiary carbocation at the $C_1$ position (where the methyl group is attached). Step $3$: Water acts as a nucleophile and attacks the tertiary carbocation to form a protonated alcohol (oxonium ion). Step $4$: Deprotonation yields the final product,$1$-methylcyclohexanol. Comparing this with the options,the primary carbocation with a positive charge on the carbon bearing the methyl group is not formed,as the initial carbocation is secondary and the final one is tertiary.

Column-$I$	Column-$II$
$A$. $CH_3-O^{+}=CH-CH_3$	$1$. Stable due to resonance
$B$. $F_3C^{+}$	$2$. Destabilised due to inductive effect
$C$. $(CH_3)_3C^{-}$	$3$. Stabilised by hyperconjugation
$D$. $CH_3-CH^{+}-CH_3$	$4$. $A$ secondary carbocation

Which of the following is not expected to be an intermediate of the following reaction?

Similar Questions

The decreasing order of stability of the following carbocations is:
$A$. $m-CH_3O-C_6H_4-CH_2^+$
$B$. $p-CH_3O-C_6H_4-CH_2^+$
$C$. $C_6H_5-CH_2^+$
$D$. $p-NO_2-C_6H_4-CH_2^+$

Identify the correct order of stability for carbocations.

Identify the correct order of stability of the following carbocations:

The increasing order of stability of the following free radicals is:

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